Is AbsX Continuous at 11

In mathematics, the symmetric derivative is an operation generalizing the ordinary derivative. It is defined as[1] [2]

lim h 0 f ( x + h ) f ( x h ) 2 h . {\displaystyle \lim _{h\to 0}{\frac {f(x+h)-f(x-h)}{2h}}.}

The expression under the limit is sometimes called the symmetric difference quotient.[3] [4] A function is said to be symmetrically differentiable at a point x if its symmetric derivative exists at that point.

If a function is differentiable (in the usual sense) at a point, then it is also symmetrically differentiable, but the converse is not true. A well-known counterexample is the absolute value function f(x) = |x|, which is not differentiable at x = 0, but is symmetrically differentiable here with symmetric derivative 0. For differentiable functions, the symmetric difference quotient does provide a better numerical approximation of the derivative than the usual difference quotient.[3]

The symmetric derivative at a given point equals the arithmetic mean of the left and right derivatives at that point, if the latter two both exist.[1] [5]

Neither Rolle's theorem nor the mean-value theorem hold for the symmetric derivative; some similar but weaker statements have been proved.

Examples [edit]

The absolute value function [edit]

Graph of the absolute value function. Note the sharp turn at x =0, leading to non-differentiability of the curve at x =0. The function hence possesses no ordinary derivative at x = 0. The symmetric derivative, however, exists for the function at x =0.

For the absolute value function f ( x ) = | x | {\displaystyle f(x)=|x|} , using the notation f s ( x ) {\displaystyle f_{s}(x)} for the symmetric derivative, we have at x = 0 {\displaystyle x=0} that

f s ( 0 ) = lim h 0 f ( 0 + h ) f ( 0 h ) 2 h = lim h 0 f ( h ) f ( h ) 2 h = lim h 0 | h | | h | 2 h = lim h 0 | h | | h | 2 h = lim h 0 0 2 h = 0. {\displaystyle {\begin{aligned}f_{s}(0)&=\lim _{h\to 0}{\frac {f(0+h)-f(0-h)}{2h}}=\lim _{h\to 0}{\frac {f(h)-f(-h)}{2h}}\\&=\lim _{h\to 0}{\frac {|h|-|{-h}|}{2h}}\\&=\lim _{h\to 0}{\frac {|h|-|h|}{2h}}=\lim _{h\to 0}{\frac {0}{2h}}=0.\\\end{aligned}}}

Hence the symmetric derivative of the absolute value function exists at x = 0 {\displaystyle x=0} and is equal to zero, even though its ordinary derivative does not exist at that point (due to a "sharp" turn in the curve at x = 0 {\displaystyle x=0} ).

Note that in this example both the left and right derivatives at 0 exist, but they are unequal (one is −1, while the other is +1); their average is 0, as expected.

The function x −2 [edit]

Graph of y = 1/x 2 . Note the discontinuity at x = 0. The function hence possesses no ordinary derivative at x = 0. The symmetric derivative, however, exists for the function at x = 0.

For the function f ( x ) = 1 / x 2 {\displaystyle f(x)=1/x^{2}} , at x = 0 {\displaystyle x=0} we have

f s ( 0 ) = lim h 0 f ( 0 + h ) f ( 0 h ) 2 h = lim h 0 f ( h ) f ( h ) 2 h = lim h 0 1 / h 2 1 / ( h ) 2 2 h = lim h 0 1 / h 2 1 / h 2 2 h = lim h 0 0 2 h = 0. {\displaystyle {\begin{aligned}f_{s}(0)&=\lim _{h\to 0}{\frac {f(0+h)-f(0-h)}{2h}}=\lim _{h\to 0}{\frac {f(h)-f(-h)}{2h}}\\&=\lim _{h\to 0}{\frac {1/h^{2}-1/(-h)^{2}}{2h}}\\&=\lim _{h\to 0}{\frac {1/h^{2}-1/h^{2}}{2h}}=\lim _{h\to 0}{\frac {0}{2h}}=0.\end{aligned}}}

Again, for this function the symmetric derivative exists at x = 0 {\displaystyle x=0} , while its ordinary derivative does not exist at x = 0 {\displaystyle x=0} due to discontinuity in the curve there. Furthermore, neither the left nor the right derivative is finite at 0, i.e. this is an essential discontinuity.

The Dirichlet function [edit]

The Dirichlet function, defined as

f ( x ) = { 1 , if x  is rational 0 , if x  is irrational {\displaystyle f(x)={\begin{cases}1,&{\text{if }}x{\text{ is rational}}\\0,&{\text{if }}x{\text{ is irrational}}\end{cases}}}

has a symmetric derivative at every x Q {\displaystyle x\in \mathbb {Q} } , but is not symmetrically differentiable at any x R Q {\displaystyle x\in \mathbb {R} \setminus \mathbb {Q} } ; i.e. the symmetric derivative exists at rational numbers but not at irrational numbers.

Quasi-mean-value theorem [edit]

The symmetric derivative does not obey the usual mean-value theorem (of Lagrange). As a counterexample, the symmetric derivative of f(x) = |x| has the image {−1, 0, 1}, but secants for f can have a wider range of slopes; for instance, on the interval [−1, 2], the mean-value theorem would mandate that there exist a point where the (symmetric) derivative takes the value | 2 | | 1 | 2 ( 1 ) = 1 3 {\displaystyle {\frac {|2|-|-1|}{2-(-1)}}={\frac {1}{3}}} .[6]

A theorem somewhat analogous to Rolle's theorem but for the symmetric derivative was established in 1967 by C. E. Aull, who named it quasi-Rolle theorem. If f is continuous on the closed interval [a,b] and symmetrically differentiable on the open interval (a,b), and f(a) = f(b) = 0, then there exist two points x, y in (a,b) such that f s(x) ≥ 0, and f s(y) ≤ 0. A lemma also established by Aull as a stepping stone to this theorem states that if f is continuous on the closed interval [a,b] and symmetrically differentiable on the open interval (a,b), and additionally f(b) > f(a), then there exist a point z in (a,b) where the symmetric derivative is non-negative, or with the notation used above, f s(z) ≥ 0. Analogously, if f(b) < f(a), then there exists a point z in (a,b) where f s(z) ≤ 0.[6]

The quasi-mean-value theorem for a symmetrically differentiable function states that if f is continuous on the closed interval [a,b] and symmetrically differentiable on the open interval (a,b), then there exist x, y in (a,b) such that[6] [7]

f s ( x ) f ( b ) f ( a ) b a f s ( y ) . {\displaystyle f_{s}(x)\leq {\frac {f(b)-f(a)}{b-a}}\leq f_{s}(y).}

As an application, the quasi-mean-value theorem for f(x) = |x| on an interval containing 0 predicts that the slope of any secant of f is between −1 and 1.

If the symmetric derivative of f has the Darboux property, then the (form of the) regular mean-value theorem (of Lagrange) holds, i.e. there exists z in (a,b) such that[6]

f s ( z ) = f ( b ) f ( a ) b a . {\displaystyle f_{s}(z)={\frac {f(b)-f(a)}{b-a}}.}

As a consequence, if a function is continuous and its symmetric derivative is also continuous (thus has the Darboux property), then the function is differentiable in the usual sense.[6]

Generalizations [edit]

The notion generalizes to higher-order symmetric derivatives and also to n-dimensional Euclidean spaces.

The second symmetric derivative [edit]

The second symmetric derivative is defined as[2] [8]

lim h 0 f ( x + h ) 2 f ( x ) + f ( x h ) h 2 . {\displaystyle \lim _{h\to 0}{\frac {f(x+h)-2f(x)+f(x-h)}{h^{2}}}.}

If the (usual) second derivative exists, then the second symmetric derivative exists and is equal to it.[8] The second symmetric derivative may exist, however, even when the (ordinary) second derivative does not. As example, consider the sign function sgn ( x ) {\displaystyle \operatorname {sgn}(x)} , which is defined by

sgn ( x ) = { 1 if x < 0 , 0 if x = 0 , 1 if x > 0. {\displaystyle \operatorname {sgn}(x)={\begin{cases}-1&{\text{if }}x<0,\\0&{\text{if }}x=0,\\1&{\text{if }}x>0.\end{cases}}}

The sign function is not continuous at zero, and therefore the second derivative for x = 0 {\displaystyle x=0} does not exist. But the second symmetric derivative exists for x = 0 {\displaystyle x=0} :

lim h 0 sgn ( 0 + h ) 2 sgn ( 0 ) + sgn ( 0 h ) h 2 = lim h 0 sgn ( h ) 2 0 + ( sgn ( h ) ) h 2 = lim h 0 0 h 2 = 0. {\displaystyle \lim _{h\to 0}{\frac {\operatorname {sgn}(0+h)-2\operatorname {sgn}(0)+\operatorname {sgn}(0-h)}{h^{2}}}=\lim _{h\to 0}{\frac {\operatorname {sgn}(h)-2\cdot 0+(-\operatorname {sgn}(h))}{h^{2}}}=\lim _{h\to 0}{\frac {0}{h^{2}}}=0.}

See also [edit]

  • Central differencing scheme
  • Density point
  • Generalizations of the derivative
  • Symmetrically continuous function

Notes [edit]

  1. ^ a b Peter R. Mercer (2014). More Calculus of a Single Variable. Springer. p. 173. ISBN978-1-4939-1926-0.
  2. ^ a b Thomson, p. 1.
  3. ^ a b Peter D. Lax; Maria Shea Terrell (2013). Calculus With Applications. Springer. p. 213. ISBN978-1-4614-7946-8.
  4. ^ Shirley O. Hockett; David Bock (2005). Barron's how to Prepare for the AP Calculus . Barron's Educational Series. pp. 53. ISBN978-0-7641-2382-5.
  5. ^ Thomson, p. 6.
  6. ^ a b c d e Sahoo, Prasanna; Riedel, Thomas (1998). Mean Value Theorems and Functional Equations. World Scientific. pp. 188–192. ISBN978-981-02-3544-4.
  7. ^ Thomson, p. 7.
  8. ^ a b A. Zygmund (2002). Trigonometric Series. Cambridge University Press. pp. 22–23. ISBN978-0-521-89053-3.

References [edit]

  • Thomson, Brian S. (1994). Symmetric Properties of Real Functions. Marcel Dekker. ISBN0-8247-9230-0.
  • A. B. Kharazishvili (2005). Strange Functions in Real Analysis (2nd ed.). CRC Press. p. 34. ISBN978-1-4200-3484-4.
  • Aull, C. E. (1967). "The first symmetric derivative". Am. Math. Mon. 74 (6): 708–711. doi:10.1080/00029890.1967.12000020.

External links [edit]

  • "Symmetric derivative", Encyclopedia of Mathematics, EMS Press, 2001 [1994]
  • Approximating the Derivative by the Symmetric Difference Quotient (Wolfram Demonstrations Project)

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Source: https://en.wikipedia.org/wiki/Symmetric_derivative

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